A bat that has more exit speed(more broken in) will have greater distance. A bat will not have less exit speed (less broken in) and give more distance not possible and I'm done... (EXIT SPEED =DISTANCE) (NOT DISTANCE>EXIT SPEED OR EXIT SPEED>DISTANCE)
TO END LET ME SAY THIS I HAVE SWUNG ALL KINDS OF BATS BUT I HAVE YET TO SAY DAMN HIS BAT HAS SOME POP ,BUT NO DISTANCE
These guys are a little slow. Since I am bored I will explain a bit more thurough.
Firstly, let me address what that one guy was saying about all bats being equal if they both have the same distance if hit at 100mph.
Yes, this is true. IF you were man enough to have BBS(batted ball speed) of 100MPH with the Easton Hammer, then yes. It will go just as far as a Helmer with a BBS of 100mph.
The difference is, some bats make it easier to reach higher BBS. Thusly a Helmer has a bigger sweet spot and more POP thusly producing more BBS versus the Hammer where it would be near impossible for it to keep up.
Secondly, A bat can not have more "pop" and have less distance. It would defy the laws of physics. Let me explain. We are going to assume when you use the word pop or exit speed we are talking about BBS. Batted ball speed is the speed at which the ball is hit off the bat. If a bat has great exit speed(lets use 100MPH as an example here) of 100MPH then it will travel further, creating distance.
If you are saying this bat has great exit speed but not the distance of "X" bat. Then it makes no sense.
You wont have a bat with lower BBS of let's say, 88MPH create more distance than the more exit speed bat of 100MPH.
If hit in the same conditions with the same trajectory a 100mph ball will travel significantly further than the 88MPH ball.
Let me give you an example.
If you drive your car to 65mph and then let off the gas and coast wouldn't the car coast further than if you were to do the same experiment but let off the gas at 45mph? Ofcourse we are talking about a controlled experiment with no variables other than speed.
This is getting long and I am sure I have lost you by now. If I haven't then I am hope this makes it clear for you the science of how exit speed = distance.