drunkducks
Addicted to Softballfans
300-310 unless your one of those people hitting shots 50ft. over the fence
290 - 305'
not to be capn buzz kill but technically there's no good answer. 276' is the answer. if you hit it high and it came straight down it could land 1' behind the fence.
276 to infinity
This is off the top of my head but simple trig shows us if the ball is coming down from 30ft at a 45 degree angle (Probably more though) and Tan= Opp/Adj or Distance/Height of fence (D/30) and you balance the equation its D=Tan45*30 which is 30 so probably a max of Thirty feet from the fence. And as the angle the ball comes down at grows, the distance need to hit a homer will decrease. 55 Degrees would be around 21 feet so unless you're hitting Monster liners that just carry, around 30 would be the max you'd need to hit it, I think.
I'm actually pretty bad a math and this is all available to be corrected. Ball speed matters a lot here but if we're going simple you need to hit the ball a max of 305 I think....
i'm gonna guess 276 feet?
yeah, the computers can model those things extremely accurately and way faster than any human can. the method i was using was basically just to draw a parabola on graph paper. with an initial height of 5ft and make it go over 30ft @ 275ft. then just see how far along the x axis it went. IRL the ball flight isnt parabolic because of air resistance, and newtonian drag, computers > me in this...
This is virtually impossible in the real world, though.
I actually tried to get this to work out in a simulation. It doesn't. Even with a 69.5* launch angle, a 136.5mph BBS, and in Flagstaff at 6900', the ball still carries 280'.
*Edit*
For how ridiculous that simulation is, the ball ends up well over 275' in the air vertically, and uses such extreme values that the ball travels 630' on a much more normal 35.5* launch angle. Even that, the closest you could get to having a ball have zero forward momentum when it crosses the fence, it still lands 5' further than the base of the fence.
In my league, we have 2 fields that have 30 ft fences. Its 275 down the line. I clear the fence about once every other game. Just wondering, anyone have a guesstimation on how far you would need to hit the ball to clear a 30 ft. fence at say, 275 ft?
This is virtually impossible in the real world, though.
It's certainly possible. It's called wind. We don't play in a vacuum.
in theory, yes. in realistic trajectories of a batted ball, no
That sounds like a complicated mathematical equation. So basically a linedrive homerun hitter would have a hard time. You would have to factor in elevation, lift, and velocity somehow. There are some popup homerun hitters out there though
not to be capn buzz kill but technically there's no good answer. 276' is the answer. if you hit it high and it came straight down it could land 1' behind the fence.
It could even land 1" behind the fence in all reality.
Outside of hurricane force headwinds or bouncing directly off the top of the fence, this isn't happening. Even with a bounce, it'd be really strange -- it would have to lose nearly all forward momentum and produce an almost perfectly vertical bounce.
So again, real world conditions put this at ~305' (+/- 5').
I'm BS'in. Hit at an absolute trajectory of 138.75fps at 98 mph. It would land at 277.5' You lost, dirtbag...
Fictional
You have to use pathaorgarean theory. And I think pi is 3.14. I'm no math whiz, so someone will need to do these calcs.
Not sure if drunk...
How does one measure trajectory in frames per second anyway? This is a new one to me.
On that note, I measured the BBS off my Recoil last night. My swing was measured at 90 Btu, and the exit speed was 117Hz. Pretty badass.
I endorse this.